240. Search a 2D Matrix II
rite an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom. For example,
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.
//O(m+n)
public class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
if(matrix.length == 0 || matrix[0].length == 0) return false;
int m = matrix.length-1;
int n = matrix[0].length-1;
int x = 0;
int y = n;
while(x <= m && y >=0){
if(matrix[x][y] == target) return true;
else if(matrix[x][y] > target) y--;
else x++;
}
return false;
}
}
O(lgm + logn ) solution
Wrong thinking, you cannot do a binary search row-wise, and then a binary search on col-wise, THIS IS TOTAL WRONG THINKING. the correct one is divide the panel to 4 parts
Check this copy paste solution.
public class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
if (matrix == null || matrix.length == 0 || matrix[0].length == 0) {
return false;
}
int m = matrix.length;
int n = matrix[0].length;
return helper(matrix, 0, m - 1, 0, n - 1, target);
}
private boolean helper(int[][] matrix, int rowStart, int rowEnd, int colStart, int colEnd, int target) {
if (rowStart > rowEnd || colStart > colEnd) {
return false;
}
int rowMid = rowStart + (rowEnd - rowStart) / 2;
int colMid = colStart + (colEnd - colStart) / 2;
if (matrix[rowMid][colMid] == target) {
return true;
}
if (matrix[rowMid][colMid] > target) {
return helper(matrix, rowStart, rowMid - 1, colStart, colMid - 1, target) ||
helper(matrix, rowMid, rowEnd, colStart, colMid - 1, target) ||
helper(matrix, rowStart, rowMid - 1, colMid, colEnd, target);
} else {
return helper(matrix, rowMid + 1, rowEnd, colMid + 1, colEnd, target) ||
helper(matrix, rowMid + 1, rowEnd, colStart, colMid, target) ||
helper(matrix, rowStart, rowMid, colMid + 1, colEnd, target);
}
}
}